Tenants lease megawatts, utilities and transformers are rated in MVA, and the gap between them is where site models go wrong.
Size a data centre substation from the critical IT load times the peak PUE, divided by the power factor, then add a spare transformer. For an illustrative 100 MW of IT at a peak PUE of 1.35 and a 0.95 power factor, the site needs 142.1 MVA of firm capacity, about 1.42 MVA per MW of IT. In an N+1 layout of three 75 MVA transformers, that means 225 MVA installed for 150 MVA firm.
Worked in full in The Data Center Development Handbook by Julian R. Sterling, with every figure reproduced in a free workbook.See the book on Amazon →
A tenant leases kilowatts of IT load. A utility, a transformer and a cable are rated in volt-amperes, because the current they carry, and the heat that limits them, depends on apparent power, not on the real power that does useful work. The two are linked by the power factor: real power (MW) = apparent power (MVA) × power factor. Part of the current a site draws is reactive, here 44.4 MVAr, which does no work in the servers but still loads every transformer on the way in. A development team that writes “120 MW” in the model when the grid offer says “120 MVA” has overstated what it can sell before it has built anything.
| Input | Value |
|---|---|
| Critical IT load to be leased, MW | 100 |
| Peak design PUE (hottest hour) | 1.35 |
| Annualised PUE, for comparison | 1.25 |
| Blended power factor at the point of connection | 0.95 |
| Transformer redundancy | N+1 |
The power factor is a blended figure. Modern UPS systems present a power factor close to one to the grid; motors, pumps and chillers less so. The design team will compute it, and the utility may set a minimum it requires at the connection point.
Step 1, real power at peak = IT load × peak PUE = 100 × 1.35 = 135.0 MW
Step 2, apparent power = 135.0 / 0.95 = 142.1 MVA (reactive part = √(142.12 − 135.02) = 44.4 MVAr)
Step 3, transformers in N+1: with three units, any two must carry the full load, so each needs 142.1 / 2 = 71.1 MVA. The next rating offered is 75 MVA.
Installed = 3 × 75 = 225 MVA; firm (one unit out) = 2 × 75 = 150 MVA, a headroom of 7.9 MVA
Excel: =IT_MW*PeakPUE/PF for MVA, and =MVA/(Units-1) for the rating each unit needs
Two shortcuts follow. The ratio is 1.42 kVA of grid capacity per kW of IT on these assumptions, a number worth checking against every grid offer. And using the annualised PUE of 1.25 instead of the peak gives 131.6 MVA, 10.5 MVA short on the one afternoon a year when it matters, the same trap described for capacity in how much leasable IT capacity a higher PUE costs.
| Layout | Rating needed per unit | Unit chosen | Installed MVA | Firm MVA | Installed / need |
|---|---|---|---|---|---|
| N+1, three units | 71.1 | 75 | 225 | 150 | 1.58 |
| N+1, four units | 47.4 | 50 | 200 | 150 | 1.41 |
| Two units, each carrying the full load | 142.1 | 150 | 300 | 150 | 2.11 |
All three deliver the same 150 MVA of firm capacity. What changes is how much transformer is bought and stands idle: 2.11 MVA installed for every MVA needed with two full-size units, 1.41 with four smaller ones. More units means less spare iron but more bays, switchgear and space in the substation compound, and the economics of that trade-off belong to the electrical engineer. The developer's job is to make sure the model uses firm capacity, never installed.
The more common question on the deal side runs the other way. A utility offers 120 MVA. How much IT can be leased?
Real power = 120 × 0.95 = 114.0 MW; leasable IT = 114.0 / 1.35 = 84.4 MW
Read 120 MVA as 120 MW and you get 120 / 1.35 = 88.9 MW: 4.4 MW too much, a 5.3 per cent overstatement
At the book's illustrative turnkey rent of $105 per kW-month, the 4.4 MW that does not exist would have been $5.60 million a year of rent in the model, before anyone capitalised it into a site value.
| Power factor | PUE 1.20 | PUE 1.35 | PUE 1.50 |
|---|---|---|---|
| 0.90 | 75.0 | 66.7 | 60.0 |
| 0.95 | 79.2 | 70.4 | 63.3 |
| 0.99 | 82.5 | 73.3 | 66.0 |
The grid is the same in every cell; the leasable capacity ranges from 60.0 to 82.5 MW. Peak PUE moves it more than the power factor, but both are worth a line in the model rather than a hard-coded MW figure. The inverse table, MVA needed for 100 MW of IT, runs from 121.2 MVA at the best corner to 166.7 at the worst.
Power procurement and grid interconnection are at the centre of the book, and the free workbook for the book's 180 MW site builds the campus economics on the same turnkey rent.
Grid MVA × power factor / peak PUE is what you can lease; IT MW × peak PUE / power factor is what you must connect. Here 100 MW of IT needs 142.1 MVA of firm capacity, delivered by 225 MVA of transformers in an N+1 layout, and a 120 MVA offer supports 84.4 MW, not 88.9.
Multiply MVA by the power factor. A 120 MVA connection at a 0.95 power factor delivers 114.0 MW of real power. Dividing by a peak PUE of 1.35 then gives 84.4 MW of IT load that can be leased. Treating the 120 MVA as 120 MW would overstate leasable capacity by 4.4 MW, or 5.3 per cent.
Peak PUE divided by power factor. At 1.35 and 0.95 it is 1.42 kVA of firm grid capacity per kW of IT. With a 1.20 peak PUE and a 0.99 power factor it falls to about 1.21, and at 1.50 and 0.90 it rises to about 1.67, so the ratio varies by more than a third across plausible designs.
That the site can lose any one transformer and still carry its full load. With three units, two must carry 142.1 MVA, so each needs 71.1 MVA and a 75 MVA rating is chosen: 225 MVA installed but 150 MVA firm. Only the firm figure should be used to size what can be leased.
This article is one calculation from The Data Center Development Handbook. The book takes the same case from first principles to the decision, chapter by chapter, and every figure it prints is a live formula in the free companion workbooks.
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